[" If two members of family "(2+lambda)x+(1+2 lambda)y-],[3(1+lambda)=0" and line "x+y=0" make an equilateral triangle,"],[" then the incentre of triangle so formed is "]

If two members of family (2+lambda)x+(1+2lambda)y-3(1+lambda) = 0 and line x+y=0 make an equilateral triangle, the the incentre of triangle so formed is

If two members of family (2+lambda)x+(1+2lambda)y-3(1+lambda) = 0 and line x+y=0 make an equilateral triangle, the the incentre of triangle so formed is

If two members of family (2+lambda)x+(1+2lambda)y-3(1+lambda) = 0 and line x+y=0 make an equilateral triangle, the the incentre of triangle so formed is

Two line from the family of lines (1+2lambda)x-(1+lambda)y+1=0 and the line x+y=5 form an equilateral triangle. The equation of the two lines can be

Three points (0,0), (3,sqrt3),(3,lambda) form an equilateral triangle. Then find the value of lambda .

If the following equations x+y-3=0,(1+lambda)x+(2+lambda)y-8=0,x-(1+lambda)y+(2+lambda)=0 are consistent then the value of lambda is

Line (1+lambda)x+(4-lambda)y+(2+lambda)=0 and (4-lambda)x-(1+lambda)y+(6-3lambda) =0 are concurrent at points A and B respectively and intersect at C then locus of centroid of DeltaABC " is " lambda is parameter

Lines (1+lambda)x+(4+lambda)y+(2+lambda)=0are(4-lambda)x-(1+lambda)y+(6-3 lambda)=0 are concurrent at points A and B respectively and intersect at C then locus of centroid of Delta ABC is (lambda is parameter )

If three points (0,\ 0),\ (3,\ sqrt(3)) and (3,\ lambda) form an equilateral triangle, then lambda= (a) 2 (b) -3 (c) -4 (d) None of these