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If lim(x->oo)((x^2+x+1)/(x+1) -ax-b)=...

If `lim_(x->oo)((x^2+x+1)/(x+1) -ax-b)=4` then a= ? b=?

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`lim_(x->oo)((x^2+x+1-ax^2-ax-bx-b)/(x+1))=4`
`lim_(x->oo)((x+1-2ax-a-b)/1)=4`
`lim_(x->oo)((x(2-2a)+1-a-b)/1)=4`
2-2a=0
a=1
1-a-b=4
a+b=-3
b=-4.
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