(vi)quad x=a(cos theta+theta sin theta),y=a(sin theta-theta cos theta)

The normal to the curve x=a(cos theta + theta sin theta), y=a(sin theta - theta cos theta) at any theta is such that

The normal to the curve x=a(cos theta + theta sin theta), y=a(sin theta - theta cos theta) at any theta is such that

The normal to the curve x=a(cos theta + theta sin theta), y=a(sin theta - theta cos theta) at any theta is such that

If x and y are connected parametrically by the equations without eliminating the parameter, find (dy)/(dx) x=a (cos theta + theta sin theta),y= a (sin theta- theta cos theta)

If x and y are connected parametrically by the equations given,without eliminating the parameter,Find (dy)/(dx)x=a(cos theta+theta sin theta),y=a(sin theta-theta cos theta)

Show that the normal at any point theta to the curve x=a(cos theta+ theta sin theta), y=a( sin theta- theta cos theta) is at a constant distance from the origin.

The normal to the curve : x=a(cos theta+theta sin theta), y = a (sin theta-theta cos theta) at any point 'theta' is such that:

The normal to the curve : x=a(cos theta+theta sin theta), y = a (sin theta-theta cos theta) at any point 'theta' is such that: