In the reaction
`PCl_(5)(g) hArr PCl_(3)(g)+Cl_(2)(g)`, the equilibrium concentrations of `PCl_(5)` and `PCl_(3)` are 0.4 and 0.2 mole `//` litre respectively. If the value of `K_(c)` is 0.5 , what is the concentration of `Cl_(2)` in moles `//` litre ?

For the reaction, PCl_(5)(g)to PCl_(3)(g)+Cl_(2)(g)

In the reaction PCl_5(g)⇔PCl_3(g)+Cl_2(g) the equilibrium concentration of PCl5 and PCl3 are 0.4 and 0.2 mole/litre respectively. If the value of KC is 0.5 what is concentration of Cl_2 in moles/litre ?

At 550 K, the value of equilibrium constant (K_(c)) is 0.08 for the given reaction: PCl_(5)hArrPCl_(3)(g)+Cl_(2)(g) occurring in a closed container. If the equilibrium concentration of PCl_(5)(g) and Cl_(2)(g) are 0.75 and 0.32 mol*L^(-1) respectively, then find the concentration of PCl_(3)(g) .

At equilibrium of the reaction PCl_5(g)⇔PCl_3(g)+Cl_2(g) the concentrations of PCl_5(g) and PCl_3(g) are 0.2 and 0.1 moles/lit.respectively K_c is 0.05. The equilibrium concentration of Cl_2

For the reaction PCl_(5)(g) hArr PCl_(3)(g)+Cl_(2)(g) the forward reaction at constant temeprature is favoured by

For the reaction: PCl_(5)(g) hArr PCl_(3)(g)+Cl_(2)(g) , if the initial concentration of PCl_(5)=1 mol/ l and x moles/litre of PCl_(5) are consumed at equilibrium, the correct expression of K_(p) if P is total pressure is