The work per unit volume to stretch the length by `1%` of a wire with cross sectional area of `1mm^2` will be. `[Y=9xx10^(11)(N)/(m^2)`]

The work done per unit volume to stretch the length of area of cross-section 2 mm^2 by 2% will be [Y= 8xx10^10N//m^2]

The work done per unit volume to stretch the length of area of cross-section 2 mm^2 by 2% will be

The workdone in increasing the length of a one metre long wire of cross - sectional area 1 m m^(2) through 1mm will be (Y=2xx10^(11)Nm^(-2)) :

The workdone in increasing the length of a one metre long wire of cross - sectional area 1 m m^(2) through 1mm will be (Y=2xx10^(11)Nm^(-2)) :

The work done in increasing the length of a one metre long wire of cross-sectional area 1 mm^(2) through 1 mm will be (Y = 2 xx 10^(11) Nm^(-2))

Calculate the force required to increase the length of a steel wire of cross- sectional area 10^(-6)m^(2) by 0.5% given: Y_(("for steel"))=2xx10^(11)N-m^(2)

A 1 m long steel wire of cross-sectional area 1 mm^(2) is extended 1 mm. If Y = 2 xx 10^(11) Nm^(-2) , then the work done is

Find the energy stored per unit volume of a steel wire of length 1m when it is stretched by 0.2mm. Given Y for steel = 2.1 x 10^11 N/m^2

What is the force requiredto stretch a steel wire of 1 cm^(2) cross-section to 1.1 times its length ? (Y = 2 xx 10^(11) N//m^(2))