The degree of dissociation of `SO_(3)` at equilibrium pressure is: `K_(p)` for `2SO_(3) (g)hArr2SO_(2)(g) + O_(2) (g)`

The degree of dissociation of SO_(3) is alpha at equilibrium pressure P_(0) . K_(P) for 2SO_(3)(g)hArr2SO_(2)(g)+O_(2)(g) is

At equilibrium degree of dissociation of SO_(3) is 50% for the reaction 2SO_(3)(g)hArr 2SO_(2)(g)+O_(2)(g) . The equilibrium constant for the reaction is

At equilibrium degree of dissociation of SO_(3) is 50% for the reaction 2SO_(3)(g)hArr 2SO_(2)(g)+O_(2)(g) . The equilibrium constant for the reaction is

Give the mathematical expression for the equlibrium constant K_(c) for the reaction. 2SO_(3)(g)hArr2SO_(2)(g)+O_(2)(g)

The equilibrium constant of the reaction, SO_(2)(g) + 1/2 O_(2)(g) hArr 2SO_(3)(g) is 5 xx 10^(-2)atm . The equilibrium constant of the reaction, 2SO_(3)(g) hArr 2SO_(2)(g) + O_(2)(g)

The equilibrium constant of the reaction SO_(2)(g) + 1//2O_(2)(g)hArrSO_(3)(g) is 4xx10^(-3)atm^(-1//2) . The equilibrium constant of the reaction 2SO_(3)(g)hArr2SO_(2)(g) + O_(2)(g) would be:

At 627^(@) C and one atmosphere SO_(3) is is partially dissociated into SO_(2) and O_(2) by SO_(3(g)) hArr SO_(2(g)) + (1)/(2) O_(2(g)). The density of the equilibrium mixture is 0.925 g/litre. What is the degree of dissociation ?

At 627^(@) C and one atmosphere SO_(3) is is partially dissociated into SO_(2) and O_(2) by SO_(3(g)) hArr SO_(2(g)) + (1)/(2) O_(2(g)). The density of the equilibrium mixture is 0.925 g/litre. What is the degree of dissociation ?

The equilibrium constant for the reaction 2SO_(2)(g)+O_(2)(g)hArr 2SO_(3)(g) is 256 at 1000 K. The equilibrium constant for the reaction : SO_(3)(g)hArr SO_(2)(g)+1//2 O_(2)(g) is :

What is the effect of increasing pressure on the equilibrium ? 2SO_(2) (g) + O_(2)(g) hArr 2SO_(3)(g)