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y=sin^(-1)x-cos^(-1)x=pi/6" ithen "x=...

y=sin^(-1)x-cos^(-1)x=pi/6" ithen "x=

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If sin^(-1)x-cos^(-1)x=(pi)/6 then x=

If sin^(-1)x-cos^(-1)x=(pi)/(6) then x=

If sin^(-1)x - cos^(-1)x=pi/6 , then: x=…..

If sin^(-1)x-cos^(-1)x=(pi)/(6), " then :" x=

If sin^(-1)x-cos^(-1)x=(pi)/(6),"then"