[" (a) "3times5(1)/(5)," (b) "5times6-(3)/(4)],[" (c) "7times2(1)/(4)," (d) "4times6(1)/(3)],[" (e) "3(1)/(4)times6," ( "b)3(2)/(5)times8]

(4)/(5)times((-2)/(3))-(2)/(5)times(1)/(3)+(3)/(5)times(4)/(5)=

(2)/(5)times(-(3)/(7))-(1)/(6)times(3)/(2)+(1)/(14)times(2)/(5)

(5)/(4)times(2)/(6)+(3)/(2)times(2)/(1)+(3)/(6)times(3)/(2)

((-4)/(3))times(1)/(2)+((-4)/(3))times((-7)/(5))

solve it : (ii) (-3)/(5)times(-3)/(5)times(-3)/(5)times(-3)/(5) (iii) (-9)/(2)times(4)/(2)times(-4)/(2)times(-4)/(2)times(-4)/(2)times(-4)/(2) (iv) (-5)/(3)times(-5)/(3)times(-5)/(3)times(-5)/(3) (v) (-6)/(2)times(-6)/(2)times(-6)/(2)times(-6)/(2)times(-6)/(2)

(2)/(5)times((-3)/(7))-(1)/(6)times(3)/(2)+(1)/(14)times(2)/(5)

( (5)/(6)-:(6)/(7)times(6)/(7)-(8)/(9)-:1(3)/(5)+(3)/(4)times3(1)/(3)

Proved that (2)/(3)times[(-6)/(7)times(4)/(5)]=[(2)/(3)times(4)/(5)]times((-6)/(7))

(6^(3)times7^(4)times8^(5))/(4^(3)times9^(2)times16)

Evaluate : ( -2/5 ) times 3/4 + 5/7 times ( -3/4 ) times 1/5