[" If "C=2cos theta," So abstract "],[Delta=|[C,1,1],[1,C,1],[6,1,C]|" What about "$?]

If C=2 cos theta , then the value of the determinant Delta= |[C,1,0],[1,C,1],[6,1,C]| is

If C=2cos theta , then the value of the determinant D=|(C,1,0),(1,C,1),(6,1,C)| is -

If C = 2 cos theta , then the value of the determinant Delta = |(C,1,0),(1,C,1),(6,1,c)| , is

If C = 2 cos theta , then the value of the determinant Delta = |(C,1,0),(1,C,1),(6,1,c)| , is

If in the determinant Delta=|[a_1,b_1,c_1],[a_2,b_2,c_2],[a_3,b_3,c_3]|,A_1,B_1,C_1 etc. be the co-factors of a_1,b_1,c_1 etc., then which of the following relations is incorrect-

Prove: cos e c\ thetasqrt(1-cos^2theta)=1

Suppose a,b, c epsilon R on abc!=0 . Let Delta=|(1+a,1,1),(1+b,1+2b,1),(1+c,1+c,1+3c)| If Delta=0 , then 1/a+1/b+1/c is equal to

If A, B and C denote the angles of a triangle, then Delta = |(-1,cos C,cos B),(cos C,-1,cos A),(cos B,cos A,-2)| is independent of

If A, B and C denote the angles of a triangle, then Delta = |(-1,cos C,cos B),(cos C,-1,cos A),(cos B,cos A,-2)| is independent of