`y=A cosx^(2) + B sinx^(2)` से अवकल समीकरण बनाइये ।

y=(sinx)^(cosx)+(cosx)^(sinx)

ysinx dy/dx=(sinx-y^2)cosx

ysinx dy/dx=(sinx-y^2)cosx

If y=sqrt(sinx+y) , then (dy)/(dx) equals (a) (cosx)/(2y-1) (b) (cosx)/(1-2y) (c) (sinx)/(1-2y) (d) (sinx)/(2y-1)

For x,yepsilonR with 0 lt x lt (pi)/2 such that ((sinx)^(2y))/((cosx)^((y^(2))/2))+((cosx)^(2y))/((sinx)^((y^(2))/2))=sin2x , then y is ________.

y=sin^(-1)((sinx+cosx)/sqrt2)=?

int (2sinx-cosx)/(2cosx+sinx)dx =

If y=sinx+cosx" then "(d^(2)y)/(dx^(2)) is :-

If y=sinx+cosx" then "(d^(2)y)/(dx^(2)) is :-