x=b sin^(2)alpha" and "y=cos^(2)thetaquad (dy)/(dx)=?

If x = a cos^(2) theta, y = b sin^(2) theta " then "(dy)/(dx)= ?

Find (dy)/(dx) : x=a sin^(2) theta cos theta, y= 2b cos^(2) theta (-sin theta)

If x = a cos theta and y = b sin theta , find (dy)/(dx)

If x = a cos theta and y = b sin theta , find (dy)/(dx)

If =a sin2 theta(1+cos2 theta),y=b cos2 theta(1-os2 theta)x=a sin2 theta(1+cos2 theta),y=b cos2 theta(1-os2 theta) and (dy)/(dx)=k tan theta then the value of k is

If x=a ( theta -sin theta ) ,y=a(1-cos theta ) ,then (dy)/(dx) =