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If b=3-a and b ne a, then (a^(2)-b^(2))/...

If `b=3-a` and `b ne a`, then `(a^(2)-b^(2))/(b-a)=`

A

3

B

1

C

0

D

`-3`

Text Solution

Verified by Experts

The correct Answer is:
D
Factor the numerator and look for something you can cancel with the denominator :
`(a^(2)-b^(2))/(b-a)=((a-b)(a+b))/(b-a)`
`= (-(b-a)(a+b))/(b-a)`
`= -(a+b)`
It's given that `b = 3-a`, which is just another way of saying a + b = 3, so
`-(a+b)=-3`
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