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If a = root(3)(t) and b = t^(2), then (b...

If `a = root(3)(t)` and `b = t^(2)`, then `(b)/(a^(5))=`

A

`t^(-(1)/(3))`

B

`t^((1)/(3))`

C

`t^((5)/(6))`

D

`t^((6)/(5))`\

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The correct Answer is:
To solve the problem, we need to find the value of \( \frac{b}{a^5} \) given that \( a = \sqrt[3]{t} \) and \( b = t^2 \). ### Step-by-Step Solution: 1. **Identify the values of \( a \) and \( b \)**: - We have \( a = \sqrt[3]{t} \) and \( b = t^2 \). 2. **Substitute the values of \( a \) and \( b \) into the expression \( \frac{b}{a^5} \)**: - Substitute \( b \) with \( t^2 \) and \( a \) with \( \sqrt[3]{t} \): \[ \frac{b}{a^5} = \frac{t^2}{(\sqrt[3]{t})^5} \] 3. **Simplify \( a^5 \)**: - Recall that \( \sqrt[3]{t} = t^{1/3} \), thus: \[ a^5 = (t^{1/3})^5 = t^{5/3} \] 4. **Rewrite the expression**: - Now we can rewrite the expression: \[ \frac{b}{a^5} = \frac{t^2}{t^{5/3}} \] 5. **Apply the laws of exponents**: - When dividing like bases, we subtract the exponents: \[ \frac{t^2}{t^{5/3}} = t^{2 - 5/3} \] 6. **Convert \( 2 \) to a fraction with a common denominator**: - Convert \( 2 \) to a fraction: \[ 2 = \frac{6}{3} \] - Now substitute: \[ t^{2 - 5/3} = t^{\frac{6}{3} - \frac{5}{3}} = t^{\frac{1}{3}} \] 7. **Final Result**: - Therefore, the final result is: \[ \frac{b}{a^5} = t^{\frac{1}{3}} \]

To solve the problem, we need to find the value of \( \frac{b}{a^5} \) given that \( a = \sqrt[3]{t} \) and \( b = t^2 \). ### Step-by-Step Solution: 1. **Identify the values of \( a \) and \( b \)**: - We have \( a = \sqrt[3]{t} \) and \( b = t^2 \). 2. **Substitute the values of \( a \) and \( b \) into the expression \( \frac{b}{a^5} \)**: ...
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KAPLAN-PRACTICE TEST 2 -PRACTICE TEST
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