Home
Class 10
MATHS
If x^(2)-8x+13 = 0, x =...

If `x^(2)-8x+13 = 0, x = `

A

`-4 pm sqrt(3)`

B

`- 4 pm 2 sqrt(3)`

C

`4 pm sqrt(3)`

D

`4pm 3sqrt(2)`

Text Solution

Verified by Experts

The correct Answer is:
C
The solution to the quadratic equation `ax^(2)+bx + c = 0` is
`x = (-b pm sqrt(b^(2)-4ac))/(2a)`
Here, `a = 1, b = -8` , and c = 13.
`x = (-(8)pm sqrt((-8)^(2)-4(1)(13)))/(2(1))=`
`(8 pm sqrt(64-4(1)(13)))/(2)`
`= (8 pm sqrt(64-52))/(2)=(8 pm sqrt(12))/(2) = (8 pm sqrt((4)(3)))/(2)`
`= (8 pm 2sqrt(3))/(2)= 4pm sqrt(3)`
Promotional Banner

Topper's Solved these Questions

  • PRACTICE TEST 3

    KAPLAN|Exercise PRACTICE TEST|50 Videos

  • QUADRATIC EQUATIONS AND THEIR GRAPHS

    KAPLAN|Exercise Multiple Choice Question|20 Videos

Similar Questions

Explore conceptually related problems

If x^(2)-8x=209, and x lt0 , what is the value of |x+3| ?

The roots of the equation x^(2) - 8x + 15 = 0 are

solve x^(2)+8x+15=0

Divide : 6x^(3) - 13x^(2) - 13x + 30 by 2x^(2) - x - 6

Solve 8x^(2)-16x=0 .

If f(x)=2x^(2)+8x+2 , for what values of x does f(x)=0?

If the roots of x^4 - 8x^3 + 14 x^2 + 8x - 15=0 are in A.P then the roots are

Solve the follwing inequations by algebric and graphical methods. i) x^(2) – 8x + 15 gt 0 ii) 2x^(2) + 3x – 2 lt 0 iii) x^(2) - 4x + 5 gt 0 iv) 15x^(2) + 4x – 5 le 0

The point from which the tangents to the circles x^2 +y^2-8x + 40 = 0,5x^2+5y^2 -25x +80=0, and x^2 +y^2-8x + 16y + 160 = 0 are equal in length, is