If one solution of `x^(2)-22x+d=0` is 6, which of the following could be the value of d ?

Options

A. 36
B. 48
C. 72
D. 96

Explanation

To solve the problem, we need to find the value of \( d \) in the quadratic equation \( x^2 - 22x + d = 0 \) given that one of the solutions is \( x = 6 \).

### Step-by-Step Solution:

1. **Substitute the known solution into the equation**:
Since \( x = 6 \) is a solution, we substitute \( x \) with \( 6 \) in the equation:
\[ 6^2 - 22 \cdot 6 + d = 0 \]

2. **Calculate \( 6^2 \)**:
\[ 6^2 = 36 \]
So the equation becomes:
\[ 36 - 22 \cdot 6 + d = 0 \]

3. **Calculate \( 22 \cdot 6 \)**:
\[ 22 \cdot 6 = 132 \]
Now substitute this back into the equation:
\[ 36 - 132 + d = 0 \]

4. **Combine the constants**:
\[ 36 - 132 = -96 \]
This simplifies our equation to:
\[ -96 + d = 0 \]

5. **Solve for \( d \)**:
To isolate \( d \), add \( 96 \) to both sides:
\[ d = 96 \]

Thus, the value of \( d \) is \( 96 \).

### Final Answer:
The value of \( d \) could be \( 96 \).