If `"Re"((z-8i)/(z+6))=0`, then lies on the curve

If "Re"((z-8i)/(z+6))=0 , then z lies on the curve

if Im((z+2i)/(z+2))= 0 then z lies on the curve :

if Im((z+2i)/(z+2))= 0 then z lies on the curve :

If Re ((z + 2i)/(z+4))= 0 then z lies on a circle with centre :

If Re ((z + 2i)/(z+4))= 0 then z lies on a circle with centre :

If z be any complex number (z!=0) then arg((z-i)/(z+i))=pi/2 represents the curve

Let I Arg((z-8i)/(z+6))=pmpi/2 II: Re ((z-8i)/(z+6))=0 Show that locus of z in I or II lies on x^2+y^2+6^x – 8^y=0 Hence show that locus of z can also be represented by (z-8i)/(z+6)+(bar(z)-8i)/(barz+6)=0 Further if locus of z is expressed as |z + 3 – 4i| = R, then find R.

If Re((z-1)/(2z+i))=1, where z=x+iy ,then the point (x,y) lies on a