`sqrt(3)cosx+sinx=1`

Solve : sqrt3cosx-sinx=1

Solve the following trigonometric equations sqrt3 cosx-sinx=1

intdx/(sqrt (3)cosx+sinx)

Find general solution of sqrt3cosx-sinx = 1

If (2+sqrt(3))cosx=1-sinx then x =

If f(x)=cos^(-1)(1/sqrt(13)(2cosx-3sinx)) +sin^(-1)(1/sqrt(13)(2cosx+3sinx)) , then find (df(x))/(dx) at x=3/4dot

Evaluate: int1/(sqrt(3)cosx+sinx)dx

cosx + sqrt(3)sinx = 1

The derivative of the function, f(x)=cos^(-1){(1)/(sqrt(13))(2cosx-3sinx)}+sin^(-1){(1)/(sqrt(13))(2cosx+3sinx)}w.r.tsqrt(1+x^(2)) is

If f(x)=cos^(-1)(1/sqrt(13))(2cosx-3sinx) +sin^(-1)(1/sqrt(13))(2cosx+3sinx)wdotrdottsqrt(1+x^2), then find (df(x))/(dx) at x=3/4dot