यदि `x= 3cos theta - 2cos ^(3) theta ,y =3sin theta - 2sin ^3theta ,` तब `dy//dx=`

x=3costheta-2cos^(3)theta, y = 3 sin theta- 2 sin^(3) theta

If x = 3 cos theta - 2 cos^3 theta,y = 3 sin theta - 2 sin^3 theta , then dy/dx is

If x=3cos theta-2cos^(3)theta,y=3sin theta-2sin^(3)theta, then (dy)/(dx) is

x = cos theta - cos 2 theta, y = sin theta - sin 2 theta . then find dy/dx

If x=3cos theta-cos^(3)theta y=3sin theta-sin^(3)theta find (dy)/(dx)

If x =3 cos theta -2 cos ^(3) theta, y=3sin theta -2 sin ^(3) theta ,then " at " theta =(pi)/(4),(dy)/(dx)

if x = "cos" theta - "cos" 2 theta, y = "sin" theta - "sin" 2 theta , then dy/dx is