" 8."(2x)/(a)+(y)/(b)=2,(x)/(a)-(y)/(b)=4

2(x/a)+(y/b)=2; (x/a)-(y/b)=4

If x=2 and y=4, then ((x)/(y))^(x-y)+((y)/(x))^(y-x)=4(b)8(c)12(d)2

If (x)/(y)=(a+2)/(a-2), then (x^(2)-y^(2))/(x^(2)+y^(2)) is equal to (8a)/(a^(2)+4)(b)(4a)/(a^(2)-4)(c)(4)/(a^(2))(d)(4a)/(a^(2)+4)

If x=2\ \ and y=4, then (x/y)^(x-y)+\ (y/x)^(y-x)= (a) 4 (b) 8 (c) 12 (d) 2

2(a x-b y)+(a+4b)=0 , 2(b x+a y)+(b-4a)=0

Factorize: (y-x)a+(x-y)b9(z-2b)^(2)+6(2b-a)(x-2y)^(2)-4x+8y2a+6b-3(a+3b)^(2)

The following are the steps involved in factorizing 64 x^(6) -y^(6) . Arrange them in sequential order (A) {(2x)^(3) + y^(3)} {(2x)^(3) - y^(3)} (B) (8x^(3))^(2) - (y^(3))^(2) (C) (8x^(3) + y^(3)) (8x^(3) -y^(3)) (D) (2x + y) (4x^(2) -2xy + y^(2)) (2x - y) (4x^(2) + 2xy + y^(2))

Factorise the following : (i) 9a^(2)-b^(2) " " (ii) 81x^(3)-x " " (iii) x^(3)-49xy^(2) " " (iv) a^(2)-(b-c)^(2) (v) (x-y)^(3)-x+y " " (vi)x^(2)y^(2)+1-x^(2)-y^(2) " " (vii) 25(a+b)^(2)-49(a-b)^(2) " " (viii) xy^(5)-x^(5)y (ix) x^(8)-256 " " (x) x^(8)-81y^(8)

Factorise the following : (i) 9a^(2)-b^(2) " " (ii) 81x^(3)-x " " (iii) x^(3)-49xy^(2) " " (iv) a^(2)-(b-c)^(2) (v) (x-y)^(3)-x+y " " (vi)x^(2)y^(2)+1-x^(2)-y^(2) " " (vii) 25(a+b)^(2)-49(a-b)^(2) " " (viii) xy^(5)-x^(5)y (ix) x^(8)-256 " " (x) x^(8)-81y^(8)