`49^(n)+16n-1` is an divisible by ________ `(n in N)`

49^(n)+16 n-1 is divisible by

49^(n)+16n-1 is divisible by

49^n + 16n -1 is divisible by

For all n in N,41^(n)-40n-1 is divisible by _________

A) 49^(n) + 16n +1 is divisible by A ( n in N) B) 3^(2n) + 7 is divisible by B ( n in N) C) 4^(n ) - 3n -1 is divisible by C ( n in n) D) 3^( 3n ) - 26 n - 1 is divisible by D (n in N) then the increasing order of A, B, C, D is

5^(n)-1 is always divisible by (n in N)

5^(n)-1 is always divisible by (n in N)

((n+2)!)/( (n-1)!) is divisible by

AA n in N, 49^(n) + 16n -1 is divisible by

7^(2n)+16n-1(n""inNN) is divisble by