[" 4."|(1+1)((2+i))/((3+i))|=],[[" (1) "-(1)/(2)," (2) "(1)/(2)]]

(1)/(1-2i)+(3)/(1+4i)

Simplify and express each of the following in the form (a + ib) : (i)" "((5)/(-3+2i)+(2)/(1-i))((4-5i)/(3+2i))" "(ii)" "((1)/(1-4i)-(2)/(1+i))((1-i)/(5+3i))

Convert each of the following in the form of (a + i b) : (i) 3(1+i)-2(2+3i) (ii) (1)/(4-5i) (iii) (1-2i)^(-2) (iv) (2-3i)/(3+5i) (v) [(1)/(1-2i)+(3)/(1+i)][(3+4i)/(2-4i)]

If i=sqrt(-)1, then 4+5(-(1)/(2)+(i sqrt(3))/(2))^(334)+3(-(1)/(2)+(i sqrt(3))/(2))^(365) is equal to (1)1-i sqrt(3)(2)-1+i sqrt(3)(3)i sqrt(3)(4)-i sqrt(3)

Simplify: (1)/(i) + (1)/(i^(2)) + (1)/(i^(3)) + (1)/(i^(4))

Simplify: (1)/(i)- (1)/(i^(2)) + (1)/(i^(3)) - (1)/(i^(4))

Convert the following in the form of (a+ib) : (i) (1+i)^(4) (ii) (-3+(1)/(2)i)^(3) (iii) (1-i)(3+4i) (iv) (1+i)(1+ 2i)(1+ 3i) (v) (3+5i)/(6-i) (vi) ((2+3i)^(2))/(2+i) (vii) ((1+ i)(2+i))/((3+i)) (viii) (2-i)^(-3)

Convert the following in the form of (a+ib) : (i) (1+i)^(4) (ii) (-3+(1)/(2)i)^(3) (iii) (1-i)(3+4i) (iv) (1+i)(1+ 2i)(1+ 3i) (v) (3+5i)/(6-i) (vi) ((2+3i)^(2))/(2+i) (vii) ((1+ i)(2+i))/((3+i)) (viii) (2-i)^(-3)

(v) (1-i) ^ (2) (1 + i) - (3-4i) ^ (2)

Simplify [ (1)/(1 - 2i ) + (3)/( 1 + i ) ][ ( 3 + 4i )/( 2 - 4i ) ]