" (4) "x+sqrt(xy)+y=1

find dy/dx if x+ sqrt (xy) + y = 1

If x+sqrt( xy)+ y=1 ,then (dy)/(dx)=

If 2y= sqrt (x+1) + sqrt (x-1) , show that 4( x^2 -1) y2 + 4xy1 - y = 0

Solution of the differential equation (y+x sqrt(xy)(x+y))dx+(y sqrt(xy)(x+y)-x)dy=0 is

If sqrt (( x)/(y)) = (24)/(5) + sqrt ((y)/(x)) and x + y = 26, then what is the value of xy ?

If sqrt(x)+sqrt(y)=17 and sqrt(x)-sqrt(y)=1, then the value of is sqrt(xy)

Simplify : (a) sqrt(y+sqrt(2xy-x^(2))) + sqrt(y-sqrt(2xy-x^(2))) (b) (x+sqrt(x^2-1))/(x-sqrt(x^(2)-1)) -(x-sqrt(x^(2)-1))/(x+sqrt(x^(2)-1))

If y = (sqrt(x+1) - sqrt(x-1)) , then prove that (x^2-1) y_2 +xy_1 = 1/4 y