[2x-3y=1],[3x-4y=1]

x-3y=1,3x-2y+4=0

Solve for (x,y) : 2x-3y =5 , 3x+4y = -1 .

The values of x, y, z for the equations x-y+z=1, 2x-y=1, 3x+3y-4z=2 are

3x+2y=1, 6x+4y=

If X+Y=[[2,-1],[1,3],[-3,2]] and X-2Y=[[-2,-1],[-3,-1],[4,-2]] find X and Y.

Solve the following pairs of equations by reducing them to a pair of linear equations: (i) 1/(2x)+1/(3y)=2 ; 1/(3x)+1/(2y)=(13)/6 (ii) 2/(sqrt(x))+3/(sqrt(y))=2 ; 4/(sqrt(x))-9/(sqrt(y))=-1 (iii) 4/x+3y=14 ; 3/x-4y=23 (iv) 5/(x-1)+1/

The normal to the curve x^(2)=4y passing (1,2) is (A) x+y=3 (B) x-y=3 (D) x-y=1

Solve the following simultaneous equations 1/(2(3x+4y)) + 1/(5(2x-3y))=1/4, 5/(3x+4y) - 2/(2x-3y) = -3/2

Consider the system of equations x-2y+3z=-1, x-3y+4z=1 and -x+y-2z=k Statement 1: The system of equation has no solution for k!=3 and Statement 2: The determinant |[1,3,-1], [-1,-2,k] , [1,4,1]| !=0 for k!=0