When `0.2 kg` of brass at `100 .^(@) C` is dropped into `0.5 kg` of water at `20 .^(@) C`,the resulting temperature is `23 .^(@) C`. The specific heat of brass is.

One kg of ice at 0^(@)C is mixed with 1 kg of water at 10^(@)C . The resulting temperature will be

One kg of ice at 0^(@)C is mixed with 1 kg of water at 10^(@)C . The resulting temperature will be

200 gram of a solid ball at 20^@C is dropped in an equal amount of water at 80^@C . The resulting temperature is 60^@C . This means that specific heat of solid is-

When a 0.45 kg of ice at 0^(@)C mixed with 0.9 kg of water at 55^(@)C in a container, the resulting temperature is 10^(@)C . Calculate the heat of fusion of ice. Specific heat of water is 4186 j kg^(-1) K^(-1) .

When 0.45 kg of ice of 0^(@)C mixed with 0.9 kg of water at 55^(@)C in a container the resulting temperature is 10^(@)C . Calculate the heat of fusion of ice .

2 kg ice at 0^@C is mixed with 8 kg of water at 20^@C . The final temperature is

When 1.5 kg of ice at 0^(@)C mixed with 2 kg of water at 70^(@)C in a container, the resulting temperature is 5^(@)C the heat of fusion of ice is ( s_("water") = 4186 j kg^(-1)K^(-1))