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The circumference of the circle x^2+y^2-...

The circumference of the circle `x^2+y^2-2x+8y-q=0` is bisected by the circle `x^2+ y^2+4x+12y+p=0`, then p+q is equal to

Text Solution

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`S_2-S_1=6x+4y+p+q=0`
`6+4(-4)+p+q=0`
`p+q=10`
Option 3 is correct.
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