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If oint(s) E.ds = 0 Over a surface, then...

If `oint_(s) E.ds = 0` Over a surface, then

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If oint_(s)vecE.vecdS=0 over a surface, then

Electric field is the electrostatic force per unit charge acting on a vanishingly small test charge placed at that point. It is a vector quantity and the electric field inside a charged conductor is zero. Electric flux phi is the total number of electric lines of force passing through a surface in a direction normal to the surface when the surface is placed inside the electric field. phi=ointvecE.vec(ds)=q/epsilon_0 If ointvecE.vec(ds)=0 over a surface, then

If underset s oint vecE.vec(ds)=0 over a surface, then

If oint_(S) vec(E ).vec(dS) = 0 over a surface then,

STATEMENT -1 : If ointvec(E).bar(ds) over a closed surface is negative,it means the surface encloses a net negative charge. STATEMENT-2 : We may have a Gaussian surface in which three lines enter and five field lines are coming out. STATEMENT-3 : The quantity ointvec(E).bar(ds) is independent of the charge distribution inside the surface.

STATEMENT -1 : If ointvec(E).bar(ds) over a closed surface is negative,it means the surface encloses a net negative charge. STATEMENT-2 : We may have a Gaussian surface in which three lines enter and five field lines are coming out. STATEMENT-3 : The quantity ointvec(E).bar(ds) is independent of the charge distribution inside the surface.

A plane EM wave travelling in vacuum along z-direction is given by E=E_(0) " sin "(kz- omegat) hati " and " B =B_(0) " sin " (kz- omegat) hatj (i) Evaluate intE. dl over the rectangular loop 1234 shown in figure. (ii) Evaluate int B.ds over the surface bounded by loop 1234. (iii) Use equation int E.dl = (-dphi_(B))/(dt) to prove (E_(0))/(B_(0)) =c. (iv) By using similar proces and the equation int B.dl =mu_(0) I+ epsilon_(0) (dphi_(E))/(dt), prove that c (1)/(sqrt(mu_(0) epsilon_(0))

A plane EM wave travelling in vacuum along z-direction is given by E=E_(0) " sin "(kz- omegat) hati " and " B =B_(0) " sin " (kz- omegat) hatj (i) Evaluate intE. dl over the rectangular loop 1234 shown in figure. (ii) Evaluate int B.ds over the surface bounded by loop 1234. (iii) Use equation int E.dl = (-dphi_(B))/(dt) to prove (E_(0))/(B_(0)) =c. (iv) By using similar proces and the equation int B.dl =mu_(0) I+ epsilon_(0) (dphi_(E))/(dt), prove that c (1)/(sqrt(mu_(0) epsilon_(0))