Molar conductivity of a weak acid HA at infinite dilution is 345.8 `cm^(2) mol^(-)` calculate molar conductivity of 0.05 M HA solution

The molar conductivity of acetic acid solution at infinite dilution is 390.7 Omega^-1 cm^2 mol^-1 . Calculate the molar conductivity of 0.01 M acetic acid solution, given that the dissociation constant of acetic acid is 1.8 xx 10^-5

The molar conductivity of acetic acid solution at infinite dilution is 390.7 Omega^(-1)cm^(2)mol^(-1) . Calculate the molar conductivity of 0.01M acetic acid solution, given that the dissociation of acetic acid is 1.8xx10^(-5) .

The molar conductance of acetic acid at infinite dilution is 390.7 S cm^(2) mol^(-1) . Calculate the molar conductance of 0.01 M acetic acid solution , given that the dissociation constant of a acetic acid is 1.8 xx 10^(-5) .

A weak monobasic acid is 5% dissociated in 0.01 mol dm^(-3) solution. The limiting molar conductivity at infinite dilution is 4.00xx10^(-2) ohm^(-1) m^(2) mol^(-1) . Calculate the conductivity of a 0.05 mol dm^(-3) solution of the acid.

A weak monobasic acid is 5% dissociated in 0.01 mol dm^(-3) solution. The limiting molar conductivity at infinite dilution is 4.00xx10^(-2) ohm^(-1) m^(2) mol^(-1) . Calculate the conductivity of a 0.05 mol dm^(-3) solution of the acid.

A 0.05 M NH_(4)OH solution offers the resistance of 50 ohm to a conductivity cell at 298 K. If the cell constant is 0.50cm^(-1) and molar conductance of NH_(4)OH at infinite dilution is 471.4ohm^(-1)cm^(2)mol^(-1) , calculate : Molar conductance

The molar conductivity of weak monobasic acid (HA) at infinite dilution is 50xx10^(-2)Omega^(-1) cm^(-2)"mol"^(-1) . The pH of 0.02M weak monobasic acid (HA) solution, whose molar conductivity is 25xx10^(-2)Omega^(-1) cm^(-2)"mol"^(-1) is:

The molar conductivity of weak electrolyte at infinite dilution can be determied by