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If x=f(t) and y=g(t) , then (d^2y)/(dx^2...

If `x=f(t)` and `y=g(t)` , then `(d^2y)/(dx^2)` is equal to `(f^(prime)g"-g'\ f")/((f^(prime))^3)` (b) `(f^(prime)g"-g'\ f")/((f^(prime))^2)` (c) `(g")/(f")` (d) `(f^g'-g"\ f')/((g^(prime))^3)`

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