When the listener moves towards a stationary source with a velocity `v_(1)` m the apparent freqency of a note emitted by the source is f' When the listener moves away from the source with the same velocity, the apparent frequency of the note f/f'=3. If v the velocity of sound in air, the value of `v//v_(1)` is -

When the listener moves towards a stationary source with a velocity V_(L) , the apparent frequency of a note emitted by the source is f' . When the listener moves away from the source with the same velocity, the apparent frequency of the note is f" . Given f'//f"=3 and V as the velocity of sound in air, the value of V/V_(L) is

When the observer moves towards the stationary source with velocity, v_1 , the apparent frequency of emitted note is f_1 . When the observer moves away from the source with velocity v_1 , the apparent frequency is f_2 . If v is the velocity of sound in air and f_1/f_2 = 2,then v/v_1 = ?

When the observer moves towards the stationary source with velocity, v_1 , the apparent frequency of emitted note is f_1 . When the observer moves away from the source with velocity v_1 , the apparent frequency is f_2 . If v is the velocity of sound in air and f_1/f_2 = 2,then v/v_1 = ?

When the observer moves towards the stationary source with velocity, 'V_1' , the apparent frequency of emitted note is ‘F_1' . When the observer moves away from the source with velocity ‘V_1’ , the apparent frequency is 'F_2' . If 'V' is the velocity ofsound in air and frac(F_1)(F_2)=2 then frac(V)(V_1)= ?

A source of sound moves towards a listener with a velocity equal to that of sound. If the source emits n waves per second, then the listener moving away from the source with the same velocity receives

The apaarent frequency of a note is 200 Hz when a listener is with a velocity of 40 ms^(-1) towards a stationary source. When he moves away from the same source with the same speed, the apparent frequency of the same note is 160 Hz. The velocity of sound in air in m/s is :