A block of mass 1kg is given horizontal velocity Vo = 10/3m/s on rough horizontal surface where 10 where U = lo 1- coefficient of friction is llo = 1. Find the maximum value of power loss (In watts) due to friction. 10 = 1073m/s TTTTTTTTTTTTTTTTTTTTTTTTT

A block of mass 1 kg is given horizontal velocity v_(0)=10sqrt(3)(m)/(s) from origin along x-axis on rough horizontal surface where coefficient of friction mu=mu_(0)(1+(x)/(10)) where mu_(0)=1 . It is found that maximum power loss due to friction is 100K in S.I units what is value of K?

A block of mass 1 kg is given horizontal velocity v_(0)=10sqrt(3)(m)/(s) from origin along x-axis on rough horizontal surface where coefficient of friction mu=mu_(0)(1+(x)/(10)) where mu_(0)=1 . It is found that maximum power loss due to friction is 100K in S.I units what is value of K?

A marble block of mass 2 kg lying on ice when given a velocity of 6 m//s is stopped by friction in 10 s. Then the coefficient of friction is:

A marble block of mass 2 kg lying on ice when given a velocity of 6 m//s is stopped by friction in 10 s. Then the coefficient of friction is -

A block of mass m is placed on a rough horizontal surface. If minimum force to pull the block is (mg)/(2) then coefficient of friction is :

A marble block of mass 2 kg lying on ice when given a velocity of 6m//s is stopped by friction in 10s. Then the coefficient of friction is

A marble block of mass 2 kg lying on ice when given a velocity of 6m//s is stopped by friction in 10s. Then the coefficient of friction is