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[" 1.If "t(n)=(1)/(4)(n+2)(n+3)" for "n=...

[" 1.If "t_(n)=(1)/(4)(n+2)(n+3)" for "n=1,2,3,......" then "],[(1)/(t_(1))+(1)/(t_(2))+(1)/(t_(3))+....+(1)/(t_(2003))=quad " [EAMCET 2003] "],[[" (a) "(4006)/(3006)," (b) "(4003)/(3007)," (c) "(4006)/(3008)," (d) "(4006)/(3009)]]

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