A solid is in the form of right circular cone surmounted on hemisphere of radius 4.2 cm and height of cone is 8 cm. The solid is placed in cylindrical tank full of water to submerge whole solid in water cylinder R=10cm , H= 19 . Find the volume of water left in cylinder.

Explanation

Volume of solid =`1/3pir^2h+ 2/3pir^3`
= `pi/3((4.2)^2*8+ 2(4.2)^3)`
=`pi/3(4.2)^2(16.4)cm^2`
Volume of cylinder=`piR^2H`
=`pi(10)^2*19=1900picm^2`

Water left in cylinder= volume of cylinder-volume of solid
=`1900pi-pi/3(4.2)^2*16.4`

=`4698.54cm^2`