A solenoid of length 0.2m has 500 turns ...

A solenoid of length 0.2m has 500 turns on it. If `8.71 xx 10^(-6) "Weber"//m^(2)` be the magnetic field at an end of the solenoid, then the current flowing in the solenoid is –

`(0.174)/(pi)A`

`(0.0174)/(pi)A`

`(17.4)/(pi)A`

`(174)/(pi)A`

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