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In an NPN transistor 10^(10) electrons e...

In an NPN transistor `10^(10)` electrons enter the emitter in `10^(-6)`s and 2 % electrons recombine with holes in base then current gain `alpha` and `beta` are

A

`alpha=0.98,beta = 49`

B

`alpha =49,beta=0.98`

C

`alpha =0.49,beta=98`

D

`alpha=98,beta=0.49`

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DISHA-SEMICONDUCTOR-physics
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