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In an AC circuit the voltage applied is ...

In an `AC` circuit the voltage applied is `E = E_(0) sin omega t`. The resulting current in the circuit is `I = I_(0) sin (omega t - (pi)/(2))`. The power consumption in the circuit is given by

A

`p=(E_(0)I_(0))/(sqrt(2))`

B

`P=sqrt(2)E_(0)l_(0)`

C

`P=(E_(0)I_(0))/(2)`

D

p = 0

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