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The energy released per fission of urani...

The energy released per fission of uranium 235 is about 200 MeV. A reactor using U-235 as fuel is producing 1000 kilowatt power. The number of U-235 nuclei undergoing fission per sec is, approximately-

A

`10^(6)`

B

`2xx10^(8)`

C

`3xx10^(16)`

D

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(a) Calculate the energy released by the fission of 2g of ._(92)U^(235) in kWh . Given that the energy released per fission is 200MeV . (b) Assuming that 200MeV of enrgy is released per fission of uranium atom, find the number of fissions per second required to released 1 kilowatt power. (c) Find the amount of energy produced in joules due to fission of 1g of ._(92)U^(235) assuming that 0.1% of mass is transformed into enrgy. ._(92)U^(235) = 235 amu , Avogadro number = 6.023 xx 10^(23)

The energy released by fission of one U^(235) atom is 200 MeV. Calculate the energy released in kWh, when one gram of uranium undergoes fission.

Knowledge Check

  • The enegry released per fission of .^(235)u is nearly

    A
    `200 eV`
    B
    `20eV`
    C
    `2000 eV`
    D
    `200MeV`
  • The energy released by the fission of one uranium atom is 200 MeV. The number of fission per second required to prodice 6.4W power is

    A
    `2xx10^(11)`
    B
    `10^(11)`
    C
    `10^(10)`
    D
    `2xx10^(10)`
  • The energy released by the fission of one uranium atom is 200 MeV. The number of fissions per second required to produce 3.2 MW of power is :

    A
    `10^(7)`
    B
    `10^(10)`
    C
    `10^(15)`
    D
    `10^(17)`
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    Assuming that 200MeV of energy is released per fission of uranium atom, find the number of fission per second required to release one kilowatt power.

    200 MeV of energy may be obtained per fission of U^235 . A reactor is generating 1000 kW of power. The rate of nuclear fission in the reactor is.

    Energy released in the fission of a single ._92 U^235 nucleus is 200 MeV . The fission rate of a ._92 U^235 fuelled reactor operating at a power level of 5 W is.

    Percentage of mass lost during the fission of ._(92)U^(235) approximately is

    If the energy released in the fission of the nucleus is 200 MeV . Then the number of nuclei required per second in a power plant of 6 kW will be.