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A metallic wire is suspended by suspendi...

A metallic wire is suspended by suspending weight to it. If S is longitudinal strain and Y its young's modulus of elasticity then potential energy per unit volume will be

A

`(1)/(2)Y^(2)S^(2)`

B

`(1)/(2)Y^(2)S`

C

`(1)/(2)YS^(2)`

D

`2YS^(2)`

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Knowledge Check

  • A metallic wire is suspended by attaching some weight to it. If alpha is the longitudinal strain and Y is Young's modulus, then the ratio of elastic potential energy to the energy density is equal to

    A
    stress on the wire
    B
    volume of the wire
    C
    strain in the wire
    D
    change in the volume of the wire

  • If s is stress and Y is Young's modulus of material, the energy stored per unit volum is

    A
    `(2Y)/(s)`
    B
    `(s)/(2Y)`
    C
    `2s^(2)Y`
    D
    `(s^(2))/(2Y)`

  • Strain energy per unit volume is given by

    A
    `(1)/(2)xx(("stress")^(2))/(y)`
    B
    `(1)/(2)xx("stress")^(2)y`
    C
    `(1)/(2)xx("strain")/("stress")`
    D
    `(1)/(2)F l`

    • Similar Questions

    Explore conceptually related problems

    A metallic wire of length L, area of cross-section A is suspended by attaching some wieght to it. If alpha is the longitudinal strain and Y is Young's modulus, find the ratio between elastic potential energy and the elastic energy density.

    What is the SI units of Young 's modulus of elasticity :

    If x is the strain produced in a wire having the Young's modulus Y, then the strain energy per unit volume is

    If in a wire of Young's moduls Y , longitudinal strain X is produced then the potential energy stored in its unit volume will be:

    The elastic energy per unit volume is terms of longitudinal strain sigma and Young's modulus Y is

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