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A conducting square loop edge length a a...

A conducting square loop edge length a and resistance R is in a uniform magnetic field B, perpendicularly. Two opposite corners of the loop are pulled apart as shown in fig., till it becomes straight, the charge flown through the loop will be -

A

`(Ba^(2))/(R)`

B

`(2Ba^(2))/(R)`

C

`(Ba^(2))/(2R)`

D

Zero

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The correct Answer is:
A
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