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A series AC circuit has a resistance of ...

A series AC circuit has a resistance of `4omega` and an inductor of reactance `3omega`. The impedance of the circuit is `z_1`. Now a capacitor of reactance `6omega` is connected in the series of above combination, the impedance becomes `z_(2)`, Then `(z_(1))/(z_(2))` will be-

A

`1 : 1`

B

`5 : 4`

C

`4 : 5`

D

`2R, Rsqrt(3)`

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The correct Answer is:
A
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