The equation of the normal to the curve parametrically represented by `x=t^(2)+3t-8 and y=2t^(2)-2t-5` at the point `P(2,-1)` is

For the curve x=t^(2) +3t -8 ,y=2t^(2)-2t -5 at point (2,-1)

For the curve x=t^(2) +3t -8 ,y=2t^(2)-2t -5 at point (2,-1)

The slope of the tangent to the curve represented by x = t^(2) + 3t - 8 and y = 2t^(2) - 2t - 5 at the point A (2,-1) is (k)/(7) , find k .

Find the equation of tangent to the curve reprsented parametrically by the equations x=t^(2)+3t+1and y=2t^(2)+3t-4 at the point M (-1,10).

Equation of the tangent and normal to the curve x=t^(2)+3t-8, y=2t^(2) -2t-5 at the point t=2 it are respectvely

The slope of tangent to the curve x=t^(2)+3t-8, y=2t^(2)-2t-5 at the point (2,-1) is …………..

The slope of the tangent to the curve x=t^(2)+3t-8,y=2t^(2)-2t-5 at the point (2,-1) is