Which one of the following compounds in a peroxide?

Options

A. `KO_(2)`
B. `BaO_(2)`
C. `MnO_(2)`
D. `NO_(2)`

Answer

B

Explanation

`KO_(2)` is `K^(+)O_(2)^(-)` i.e., superoxide
`BaO_(2)` is `Ba^(2+)O_(2)^(2-)` i.e., peroxide
`MnO_(2)` is `Mn^(4+)O^(2-)` i.e., monoxide
`NO_(2)` is `N^(4-)O^(2-)` i.e., monoxide