`AtoB` (zero order reaction)
`CtoD` (first order reaction)
In first order reaction gets `75%` completed in 40 min and zero order reaction gets `75%` completed in 30 min then calculate the value of Z where
`Z=("Half life period of first order reaction")/("Half life period of zero order reaction")`

Answer

1

Explanation

`Z=(((t_((3)/(4)))/(2))1^(st) "order")/(((2t_((3)/(4)))/(3))"zero order")`
`=((40)/(2))/(((2xx30)/(3)))=1.0`