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0.2 mol A(x)B(y)to0.5 mol A(2)+0.4molB(3...

0.2 mol `A_(x)B_(y)to0.5` mol `A_(2)+0.4molB_(3)`. From this data the molecular formula of AB

A

`AB_(2)`

B

`A_(2)B_(2)`

C

`A_(4)B_(5)`

D

`A_(5)B_(6)`

Text Solution

Verified by Experts

The correct Answer is:
D

`A_(x)B_(y)toA_(2)B_(3)`
`{:(0.2mol,0.5mol,0.4mol),(1mol,2.5mol,2mol):}` `=2.5xx2` `2xx3`
`=5molA=6molB`
`becauseMF=A_(5)B_(6)`
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