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For reaction NH(3)(liq.)+Naoverset(warm)...

For reaction `NH_(3)(liq.)+Naoverset(warm)toP+Quarr` Incorrect statement is:

A

Hydrolysis of `P` produces `NH_(3)` gas.

B

Gas `Q` reacts with heated alkali metals.

C

Anionic part of `P` is weaker base than `NH_(3)`

D

Gas Q is also produced, when Li metal is heated with `NH_(3)` gas

Text Solution

Verified by Experts

The correct Answer is:
C
`Na+NH_(3)(liq.)overset(warm)toNaNH_(2)+(1)/(2)H_(2)(g)`
(A). Hydrolysis of `NaNH_(2)`
`NaNH_(2)+H_(2)O+H_(2)OtoNaOH+NH_(3)`
(B). Alkali metal `+H_(2)overset(Delta)to` mwetal hydride
(C). `NH_(2)^(-)` is stronger base than `NH_(3)`
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