Home
Class 12
CHEMISTRY
alpha- maltose (C(12)H(22)O(11)) can be ...


`alpha`- maltose `(C_(12)H_(22)O_(11))` can be hydrolysed to glucose `(C_(6)H_(12)O_(6))` according to the following reaction.
`C_(12)H_(22)(O_(11)(aq)+H_(2)O(l)to2C_(6)H_(12)O_(6)(aq)`
Given:
Standard enthalpy of formation of `C_(12)H_(22)O_(11)(aq)=-2238(kJ)/(mol)`
Standard enthalpy of formation of `H_(2)O(l)=-285(kJ)/(mol)`
Standard enthalpy of formation of `C_(6)H_(12)O_(6)(aq)=-1263(kJ)/(mol)`
Which of the following statements (s) is/are true?

A

the hydrolysis of `alpha`- maltose is exothermic.

B

Heat liberated in combustion of 1.0 mol of `alpha`- moltose is greater than the heat liberated in combustion of 2.0 mol of glucose.

C

Increasing temperature will increase the degree of hydrolysis of `alpha`- maltose

D

The hydrolysis of `alpha`- maltose follow `1^(st)` order kinetics.

Text Solution

Verified by Experts

The correct Answer is:
A, B, D
(A). `DeltaH=[2(-1263)]-[(-2238)+(-285)]=-3kJ`
(B). `C_(12)H_(22)O_(11)+12O_(2)to12CO_(2)+11H_(2)O`
`{C_(6)H_(12)O_(6)6O_(2)to6CO_(2)+6H_(2)O}xx2`
`C_(12)H_(22)O_(11)+H_(2)Oto2C_(6)H_(12)O_(5),DeltaH=-3kJ` ltbr. (C). Hydrolysis is exothermic `Tuarrhdarr`
(D). Concentration becomes one-fourth in equal tim interval. Hence `1^(st)` order.
Promotional Banner

Similar Questions

Explore conceptually related problems

The enthalpy of the reaction : H_(2)O_(2)(l)toH_(2)O(l)+(1)/(2)O_(2)(g) is -23.5 kcal mol^(-1) and the enthalpy of formation of H_(2)O(l) is -68.3 kcal mol^(-1) . The enthalpy of formation of H_(2)O_(2)(l) is

Complete the reactions : C_(12)H_(22)O_(11) + H_(2)SO_(4) ("conc.") →

What is the equivalent weight of C_(12)H_(22)O_(11) in the following reaction? C_(12)H_(22)O_(11)+36HNO_(3) rarr 6H_(2)C_(2)O_(4)+36NO_(2)+23H_(2)O

What is the O.N of C in C_(6)H_(12)O_(6) ?

Consider the reaction, C_(6)H_(12)O_(6)(g)+6O_(2)(g) to 6CO_(2)(g) +6H_(2)O(l) , which of the following expressions is /are correct?