" (a) "(x+y)^(2)-2(x+y)(x-y)+(x-y)^(2)

The axis of a parabola is along the line y=x and the distance of its vertex and focus from the origin are sqrt(2) and 2sqrt(2) , respectively. If vertex and focus both lie in the first quadrant, then the equation of the parabola is (a) (x+y)^2=(x-y-2) (b) (x-y)^2=(x+y-2) (c) (x-y)^2=4(x+y-2) (d) (x-y)^2=8(x+y-2)

The factors of x^3-x^2y-x y^2+y^3 are (a (x+y)(x^2-x y+y^2) (b) (x+y)(x^2+x y+y^2) (c) (x+y)^2(x-y) (d) (x-y)^2(x+y)

The following steps are involved in the factorisation of x^(2) (x - y) + (y-x) y^(2) . Arrange them in sequential order from the first to the last . (A) (x-y) [x^(2) - y^(2)] (B) x^(2)(x-y) - ( x- y) y^(2) (C) (x-y)^(2) (x + y) (D) (x-y) [(x + y)( x-y)]

The factors of x^(3)-x^(2)y-xy^(2)+y^(3) are (a (x+y)(x^(2)-xy+y^(2))(b)(x+y)(x^(2)+xy+y^(2))(c)(x+y)^(2)(x-y)(d)(x-y)^(2)(x+y)

The axis of a parabola is along the line y=x and the distance of its vertex and focus from the origin are sqrt(2) and 2sqrt(2), respectively.If vertex and focus both lie in the first quadrant, then the equation of the parabola is (x+y)^(2)=(x-y-2)(x-y)^(2)=4(x+y-2)(x-y)^(2)=4(x+y-2)(x-y)^(2)=4(x+y-2)(x-y)^(2)=8(x+y-2)

The axis of a parabola is along the line y=x and the distance of its vertex and focus from the origin are sqrt(2) and 2sqrt(2) , respectively. If vertex and focus both lie in the first quadrant, then the equation of the parabola is (x+y)^2=(x-y-2) (x-y)^2=(x+y-2) (x-y)^2=4(x+y-2) (x-y)^2=8(x+y-2)

What is ((x^(2)+y^(2))(x-y)-(x-y)^(3))/(x^(2)y-xy^(2)) equal to ?