[" If "4a^(2)+9b^(2)-c^(2)+12ab=0" then the "],[" is concurrent at "]

Statement I: The points (a,0),(0,b) and (1,1) will be collinear if 1/a+1/b=1 Statement II: If 4a^(2)+9b^(2)-c^(2)+12ab=0 , then the family of lines ax+by+c=0 is either concurrent at (2,3) or at (-2,-3). Then which of the followng is true

If 4a^(2)+9b^(2)-c^(2)+12ab=0 , then the set of lines ax+by+c=0 pass through the fixed point

If 4a^(2)+9b^(2)-c^(2)+12ab=0 , then the set of lines ax + by+c = 0 pass through the fixed point

For three positive real numbers a,b,c,a>b, if a^(2)+b^(2)-c^(2)-2ab=0 the point of concurrency of the straight lines ax+by+c=0 lies on

If 4a^(2)+9b^(2)-c^(2)+12ab=0 then the family of straight lines ax+by+c=0 is concurrent at : (A)(-3,2) or (2,3)(B)(-2,3) or (2,-3)(C)(3,2) or (-3,-2)(D)(2,3) or (-2,-3)

If 4a^(2)+9b^(2)-c^(2)-12ab=0 then family of straight lines ax+by+c=0 are concurrent at P and Q then values of P & Q are

If a^(2)+4b^(2)-9c^(2)=4ab , then the line on which is meet the point of concurrency of family of straight line ax+by+3c=0 lies is

If 6a^(2)+12b^(2)+2c^(2)+17ab-10bc-7ac=0 then all the lines represented by ax+by+c=0 are concurrent at the point