(2a+1)^(3)+(a-1)^(2)

2[((1)/(2))+(1)/(3)((1)/(2))^(3)+(1)/(5)((1)/(2))^(5)+...]=

(2)/(3) -((1)/(2) -(1)/(3))/((1)/(2)+(1)/(3))xx3(1)/(3)+(5)/(6) =?

Simplify each of the following : [{((-1)/5)^(-2)}^2]^(-1)\ (ii) {(1/3)^(-2)-\ (1/2)^(-3)}-:(1/4)^(-2)

Simplify each of the following : (i) [{((-1)/5)^(-2)}^2]^(-1)\ (ii) {(1/3)^(-2)-\ (1/2)^(-3)}-:(1/4)^(-2)

The sum of the first 35 terms of the series (1)/(2) + (1)/(3) -(1)/(4) -(1)/(2) -(1)/(3) +(1)/(4) +(1)/(2) + (1)/(3) -(1)/(4)

Let H_(n)=1+(1)/(2)+(1)/(3)+ . . . . .+(1)/(n) , then the sum to n terms of the series (1^(2))/(1^(3))+(1^(2)+2^(2))/(1^(3)+2^(3))+(1^(2)+2^(2)+3^(2))/(1^(3)+2^(3)+3^(3))+ . . . , is

The normal to the curve y(x-2)(x-3)=x+6 at the point where the curve intersects the y-axis,passes through the point :((1)/(2),-(1)/(3))(2)((1)/(2),(1)/(3))(3)(-(1)/(2),-(1)/(2))(4)((1)/(2),(1)/(2))

The expression (2^(2)+1)/(2^(2)-1)+(3^(2)+1)/(3^(2)-1)+(4^(2)+1)/(4^(2)-1)+((2011)^(2)+1)/((2011)^(2)-1) lies in the interval

If A=[(2,2,1),(1,3,1),(1,2,2)] then A^(-1)+(A-5I)(A-I)^(2)=