At 298 K 1.0 g of a non-colatile solute is dissoved in 100 g of acetone (mol mass=58). The vapour pressure of the solution at this temperature is found to be 192.5 mm Hg. Calculate themolar mass of the solute. The vapour pressure of pure acetone at 298 K is found to be 195 mm Hg.

1.0 gram of a non-volatile solute was dissolved in 100 gram of acetone (molecular mass = 58) at 298 K. The vapour pressure of solution was found to be 192.5 mm of Hg. Calculate the molecular mass of solute. The vapour pressure of pure acetone at 298 K is 195 mm of Hg.

In an experiment ,1 g of a non-volatile solute was disslved in 100 g of acetone ( molarcular mass = 58 ) at 298 K . The vapour pressure of the solution was found to be 192.5 mm Hg .The molecular weight of the solute is _________ g mol ^(-1) ( vapour pressure of acetone = 195 mm Hg )

5.8 g of non - volatile, non - electrolyte solute was dissolved in 100 g of carbon disuiphide (CS_(2)) . The vapour pressure of the solution was found to be 190 mm of Hg. Calculate molar mass of the solute. Given : Vapour of pure CS_(2) is 195 mm of Hg and molar mass of CS_(2) is 76g//mol .

The vapour pressure of 2.1% solution of a non-electrolyte in water at 100^@C is 755 mm Hg. Calculate the molar mass of the solute. (58.69 g mol^(-1)

The vapour pressure of a 10% aqueous solution of a non volatile substance at 373K is 740 mm of Hg. Calculate the molecular mass of the solute.