Elevation in `b.p.` of an aqueous urea solution is `0.52^(@), (K_(b)=0.622^(@) "mol"^(-1)kg)` Hence, mole-fraction of urea in this solution is :

Elevation in b.p of an aqueous urea solution is 0.52^(0). (K_(b)=0.52^(0)"mol"^(-1)kg ). Hence, mole -fraction of urea in this solution is :

Figure explains elevation in boiling point when a non-volatile solute is added to a solvent. Variation of vapour pressure with temperaure and elevation in boiling point is marked. Elevation in b.p of an aqueous urea solution is 0.52^(@) (K_(b) = 0.52^(@) mol^(-1)kg) . Hence, mole fraction of urea in this solution is:

Figure explains elevation in boiling point when a non-volatile solute is added to a solvent. Variation of vapour pressure with temperaure and elevation in boiling point is marked. Elevation in b.p of an aqueous urea solution is 0.52^(@) (K_(b) = 0.52^(@) mol^(-1)kg) . Hence, mole fraction of urea in this solution is:

Consider following figure and answer the questions at the end of it. Figure explains elevation in boiling point when a non-volatile solute is added to a solvent. Variation of vapour pressure with temperature and showing elevation in boiling point. Elevation in boiling point of an aqueous urea solution is 0.52^(@).(K_(b)=0.52^(@)mol^(-1)kg) . Hence, mole fraction of urea in this solution is:

Depression in f.p. of an aqueous urea solutio is 1.86^(@) .(K_(f)=1.86^(@) mol^(-1) kg) Hence, mole - fraction of urea in this soluiton is :

Depression in f.p. of an aqueous urea solutio is 1.86^(@) .(K_(f)=1.86^(@) mol^(-1) kg) Hence, mole - fraction of urea in this soluiton is :

Elevation in boiling point of an aqueous solution of urea is 0.52 ( k_(b) "for water"=0.52K"molality"^(-1)) . The mole fraction of urea in this solution is :

Elevation in boiling point of an aqueous solution of urea is 0.52 ( k_(b) "for water"=0.52K"molality"^(-1)) . The mole fraction is urea in this solution is :